Hey Everyone, I hope this helps!

### Challenge!!!

Wednesday, March 18, 2009

Hey Everyone! I'm not sure if Mr. H want's me to write here, {please let me know if this is bad haha} but my name is Chantelle and I am going to the U of Regina and have been invited to your Blog!!!

I came across a question in one of my math classes that I feel will be right up your alley with Pythagorean Theorem! So here is a little challenge for you!

The question is: The perimeter of an isosceles triangle {2 sides are equal and the two angles at the base are equal} ABC with AB=BC is 128 inches. The altitude {height of the triangle which is perpendicular (90 degree angle) to the base ( and in the case of an isosceles triangle, hits at the midpoint of the base)} BD is 48 inches. What is the area of the triangle??

So, you will need a couple formulas other than just pythagorus. However, I think you can do it!

This is from my Math 308 class, which is a 4th year math class!!!

Good Luck!!

I came across a question in one of my math classes that I feel will be right up your alley with Pythagorean Theorem! So here is a little challenge for you!

The question is: The perimeter of an isosceles triangle {2 sides are equal and the two angles at the base are equal} ABC with AB=BC is 128 inches. The altitude {height of the triangle which is perpendicular (90 degree angle) to the base ( and in the case of an isosceles triangle, hits at the midpoint of the base)} BD is 48 inches. What is the area of the triangle??

So, you will need a couple formulas other than just pythagorus. However, I think you can do it!

This is from my Math 308 class, which is a 4th year math class!!!

Good Luck!!

### Scribe Post, March 10, 2009

Tuesday, March 10, 2009

Since Renz forgot to choose a person to do the next scribe, I'll do it. But.. just to tell everyone, I AM ALREADY 2 SCRIBES AHEAD or maybe one. So, please don't pick me to be next and please don't forget to pick someone to do the next scribe!

This second square has an area of 2. It is NOT a perfect square because the square root of 2 is 1.414, which is obviously not a perfect number. So, the square cannot have a perfect sideline either. Squareroot2 = 1.414, 1.414x1.414 and 1.414 squared. This square is between the first and last square. This square would not be able to get into the perfect square club because the sidelines have decimals in them.

Today in Math class, we first corrected our homework from yesterday.

To join the perfect square club, you must be a full NUMBER, no decimals. EG: 4x4

If you do not belong to the perfect square club, you are imperfect. You are not a PERFECT sideline number, you are not a full number. You have a demical. EG: 4.5x4.5

After we corrected out homework, Harbeck drew us 4 squares.

Just like this picture v. He then told us to describe it and write down 3 things about each square.

The first square has an area of 1. It is an all perfect square because one is one square unit. The sidelines are 1, and you get this by square rooting the area (1). so, squareroot1 = 1. So, 1x1, and 1 squared. This square is also the smallest square out of all of them, and it also belongs in the perfect square club because the sideline numbers are perfect numbers and don't have decimals.

The first square has an area of 1. It is an all perfect square because one is one square unit. The sidelines are 1, and you get this by square rooting the area (1). so, squareroot1 = 1. So, 1x1, and 1 squared. This square is also the smallest square out of all of them, and it also belongs in the perfect square club because the sideline numbers are perfect numbers and don't have decimals.

The third square has an area of 3. It is NOT a perfect square, because the square root of 3 is 1.732, which again is obviously not a perfect number. so the square cannot have a perfect sideline either. Squareroot3 = 1.732, 1.732x1.732, 1.732 squared. This square is between the first and last square. This square would not be able to get into the perfect square club because the sidelines have decimals in them.

The last square has an area of 4. It is a perfect square because the square root of 4 is 2 which is a perfect number. Squareroot4 = 2, 2x2, 2 squared. This is also the largest square in the whole picture, and it also belongs in the perfect square club because the sideline number is a full number with no decimals.

And lastly, he gave us homework.

HOMEWORK:

Make 9 squares and write down 3 things about them, and explain how they all fit together.

Heres what I think the answers are. (Sorry, It would take too long to draw 30 squares on paint.)

Square 5 - The square has an area of 5. It is not a perfect square because the square root of 5 is 2.236, which is obviously not a perfect number. This square would not belong in the perfect square club because the sideline numbers are not full numbers. (decimals). Squareroot5 = 2.236, 2.236x2.236, 2.235 squared. You can also find the perimeter by adding all the sideline numbers together. 2.236+2.236+2.236+2.236=8.944.

Square 5 - The square has an area of 5. It is not a perfect square because the square root of 5 is 2.236, which is obviously not a perfect number. This square would not belong in the perfect square club because the sideline numbers are not full numbers. (decimals). Squareroot5 = 2.236, 2.236x2.236, 2.235 squared. You can also find the perimeter by adding all the sideline numbers together. 2.236+2.236+2.236+2.236=8.944.

Square 6 - This square has an area of 6. It is not a perfect square once again, because the squareroot of 6 is 2.448, which is obviously not a perfect number. This square would not belong in the perfect square club because the sideline numbers are not full numbers once again. Squareroot6 = 2.448, 2.448x2.448 and 2.448 squared. You can also find the perimeter by adding all the sideline numbers together. 2.448+2.448+2.448+2.448=9.792.

Square 7 - This square has an area of 7. It is not a perfect square because the square root of 7 is 2.645, which is obviously not a perfect number. This square would not belong in the perfect square club because the sideline numbers are not full numbers once again. Squareroot7 = 2.645. 2.645x2.645, and 2.645 squared. You can also find the perimeter of the square by adding all the sidelines of the numbers together. 2.645+2.645+2.645+2.645=10.58

Square 8 - This square has an area of 8. It is not a perfect square because the square root of 8 is 2.828, which is obviously once again not a perfect number. This square would NOT belong in the perfect square club because the sideline numbers are not full numbers. Squareroot8 = 2.828, 2.828x2.828, and 2.828 squared. You can also find the perimeter by adding all the sideline numbers together. 2.828+2.828+2.828+2.828=11.312.

Square 9 - This square has an area of 9. It is a perfect square because the square root of 9 is 3, which is obviously a perfect number. This square would definitely belong in the perfect square club because the sideline numbers are full numbers. Square root 9 = 3, 3x3 and 3 squared. You can also find the perimeter by adding all the sideline numbers together. 3+3+3+3=12.

WELL, there. I don't really understand the last part of the homework, so I'll wait until tomorrow and see. I thought we had to talk about 30 squares! and I did 27, but then that time I checked my books and asked many people. And they all said 9. So, booo me. Anyways, thanks for reading! PLEASE comment. NEXT SCRIBE, I CHOOOOSE..... DEAN.

### March 9 scribe (Renz)

Monday, March 9, 2009

Today we talked about perfect squares and charts which in this case is the multiplication table chart.

So Harbeck was talking about the multiplication charts and squares and stuff and then harbeck made us write down and finish a multiplication chart like so:

Yeah so it's not pretty but this was what we had to copy down for the chart.

Then we talked about some multiplication stuff and then we wrote down some multiplication questions like 1 squared then Harberck made us write it till 30 squared then we had to write it out 1 to 30 in standard form (eg., 2x2). so then this is what it looked like.

Okay so this was the sheet that we had to make with the multplication and the exponents and then we had to figure out the answers then we had to look at it and look for a pattern and from what i see i think that the pattern is that it is always being added with a odd number to make the second number(eg. 30x30= 900 or in the pattern it would be like 59+841=900).

Then after we did those things and finished them, then Harbeck gave us our homework.

We had three homework for the day:

1.we had to colour our grid with different colour by row.

2.then make a rule about the chart and the patterns.

3. Then finish the times table with all the numbers placed in order for the multiplication chart.

So then this is what we talked about and worked on for this class.

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