### Challenge!!!

Wednesday, March 18, 2009
Hey Everyone! I'm not sure if Mr. H want's me to write here, {please let me know if this is bad haha} but my name is Chantelle and I am going to the U of Regina and have been invited to your Blog!!!

I came across a question in one of my math classes that I feel will be right up your alley with Pythagorean Theorem! So here is a little challenge for you!

The question is: The perimeter of an isosceles triangle {2 sides are equal and the two angles at the base are equal} ABC with AB=BC is 128 inches. The altitude {height of the triangle which is perpendicular (90 degree angle) to the base ( and in the case of an isosceles triangle, hits at the midpoint of the base)} BD is 48 inches. What is the area of the triangle??

So, you will need a couple formulas other than just pythagorus. However, I think you can do it!
This is from my Math 308 class, which is a 4th year math class!!!

Good Luck!!

1. kuung 841 said...

Hello Chantelle. Sorry I'm not going to solve the math question .. until probably later. Haha, because I'm not smart enough :) Welcome to our math blog, and I hope you have fun .. with our class 8-)

March 18, 2009 at 6:04 PM

2. Chantelle B said...

Don't think that way. Draw it out and it will come to you!! I wouldn't have put this on if I did not think you could do it!

March 18, 2009 at 6:43 PM

3. Mr. H said...

Great Problem. Will get the kids to do it tomorrow in class. If you add a picture they would understand it more. Great Idea.

March 18, 2009 at 7:00 PM

4. Mr. H said...

To insert a picture make sure it is a .png or jpg. If you made one in paint you need to save as .jpg. Then upload to blogger using the image button on your toolbar.

March 18, 2009 at 7:01 PM